The intensity of the magnetic induction field | vedclass

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Question

(A) The formula for the magnetic field at the center of a circular coil is given by $B = \frac{\mu_0 I}{2r}$.Given values are:Permeability of free spa

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$36 \pi 	imes 10^{-7} \,T$

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(A) The formula for the magnetic field at the center of a circular coil is given by $B = \frac{\mu_0 I}{2r}$.Given values are:Permeability of free space,$\mu_0 = 4\pi 	imes 10^{-7} \,T \cdot m/A$Current,$I = 0.9 \,A$Radius,$r = 5 \,cm = 5 	imes 10^{-2} \,m$Substituting these values into the formula:$B = \frac{4\pi 	imes 10^{-7} 	imes 0.9}{2 	imes 5 	imes 10^{-2}}$$B = \frac{3.6\pi 	imes 10^{-7}}{10 	imes 10^{-2}}$$B = \frac{3.6\pi 	imes 10^{-7}}{10^{-1}}$$B = 3.6\pi 	imes 10^{-6} \,T$$B = 36\pi 	imes 10^{-7} \,T$

The intensity of the magnetic induction field at the centre of a single turn circular coil of radius $5 \,cm$ carrying a current of $0.9 \,A$ is:

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