The intensity of radiation emitted by the Sun | vedclass

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(B) According to Wien's displacement law,the product of the absolute temperature $T$ and the wavelength $\lambda_m$ corresponding to maximum intensity

Vedclass · Accepted Answer

$0.69$

Vedclass · Answer

(B) According to Wien's displacement law,the product of the absolute temperature $T$ and the wavelength $\lambda_m$ corresponding to maximum intensity is a constant:$T \lambda_m = b$This implies $T \propto \frac{1}{\lambda_m}$.Given:$\lambda_S = 510 \ nm$ (wavelength for the Sun)$\lambda_N = 350 \ nm$ (wavelength for the North Star)Therefore,the ratio of the surface temperature of the Sun $(T_S)$ to the North Star $(T_N)$ is:$\frac{T_S}{T_N} = \frac{\lambda_N}{\lambda_S}$Substituting the values:$\frac{T_S}{T_N} = \frac{350}{510} \approx 0.686 \approx 0.69$.

The intensity of radiation emitted by the Sun has its maximum value at a wavelength of $510 \ nm$ and that emitted by the North Star has the maximum value at $350 \ nm$. If these stars behave like black bodies,then the ratio of the surface temperature of the Sun and the North Star is

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