The input resistance of a common emitter tran | vedclass

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Question

(A) Given: $\alpha = 0.98$,$R_o = 500 \, k\Omega = 500 	imes 10^3 \, \Omega$,Power Gain $= 6.0625 	imes 10^6$.First,calculate the current gain $\bet

Vedclass · Accepted Answer

$198$

Vedclass · Answer

(A) Given: $\alpha = 0.98$,$R_o = 500 \, k\Omega = 500 	imes 10^3 \, \Omega$,Power Gain $= 6.0625 	imes 10^6$.First,calculate the current gain $\beta$ for the common emitter configuration:$\beta = \frac{\alpha}{1 - \alpha} = \frac{0.98}{1 - 0.98} = \frac{0.98}{0.02} = 49$.The formula for power gain in a common emitter amplifier is:$	ext{Power Gain} = \beta^2 	imes \frac{R_o}{R_{in}}$.Substituting the known values:$6.0625 	imes 10^6 = (49)^2 	imes \frac{500 	imes 10^3}{R_{in}}$.$6.0625 	imes 10^6 = 2401 	imes \frac{500 	imes 10^3}{R_{in}}$.$R_{in} = \frac{2401 	imes 500 	imes 10^3}{6.0625 	imes 10^6}$.$R_{in} = \frac{1200500 	imes 10^3}{6.0625 	imes 10^6} = \frac{1200.5 	imes 10^6}{6.0625 	imes 10^6} \approx 198 \, \Omega$.

The input resistance of a common emitter transistor amplifier,if the output resistance is $500 \, k\Omega$,the current gain $\alpha = 0.98$ and power gain is $6.0625 \times 10^6$,is ......... $\Omega$.

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