The increasing order of the ionic radii of th | vedclass

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(C) For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number,$Z$) increases.All the given species,$S^{2-}, Cl^{-}, K^

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$Ca^{2+}, K^{+}, Cl^{-}, S^{2-}$

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(C) For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number,$Z$) increases.All the given species,$S^{2-}, Cl^{-}, K^{+},$ and $Ca^{2+}$,contain $18$ electrons.Their respective atomic numbers $(Z)$ are: $S = 16, Cl = 17, K = 19, Ca = 20$.Since the ionic radius is inversely proportional to the nuclear charge for isoelectronic species,the increasing order of ionic radii is: $Ca^{2+} < K^{+} < Cl^{-} < S^{2-}$.

The increasing order of the ionic radii of the given isoelectronic species is:

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