The increasing order of the crystal field splitting power of some common ligands is
- A$H_2O < NO_2^- < CN^- < NH_3$
- B$NH_3 < NO_2^- < CN^- < H_2O$
- C$H_2O < NH_3 < NO_2^- < CN^-$
- D$H_2O < NH_3 < CN^- < NO_2^-$
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The crystal field stabilization energy $(CFSE)$ of $[Fe(H_2O)_6]Cl_2$ and $K_2[NiCl_4]$,respectively,are
DifficultJEE MAIN 2019
View SolutionWhat is the electronic arrangement of a metal atom/ion in an octahedral complex with $d^4$ configuration,if $\Delta_{0} < P$ (pairing energy)?
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View SolutionIn which of the following complexes will the $CFSE$ (Crystal Field Stabilization Energy),$\Delta_0$ be equal to zero?
Arrange the following in increasing order of their crystal field splitting energy:
$I. [Co(H_2O)_6]^{3+}$
$II. [Co(NH_3)_6]^{3+}$
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$I. [Co(H_2O)_6]^{3+}$
$II. [Co(NH_3)_6]^{3+}$
$III. [Co(CN)_6]^{3-}$
$IV. [CoF_6]^{3-}$
$[Fe(H_2O)_6]^{3+}$ is strongly paramagnetic whereas $[Fe(CN)_6]^{3-}$ is weakly paramagnetic. Explain.
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