The increasing order of O-N-O bond angle in t | vedclass

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(D) The bond angles for the given species are as follows:$1.$ $NO_2^+$: It has $sp$ hybridization and a linear geometry,resulting in a bond angle of $

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None of these

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(D) The bond angles for the given species are as follows:$1.$ $NO_2^+$: It has $sp$ hybridization and a linear geometry,resulting in a bond angle of $180^\circ$.$2.$ $NO_2$: It has $sp^2$ hybridization with one unpaired electron,resulting in a bond angle of approximately $134^\circ$.$3.$ $NO_2^-$: It has $sp^2$ hybridization with one lone pair,resulting in a bond angle of approximately $115^\circ$.Comparing these values,the increasing order of the bond angle is $NO_2^- Since this specific order is not listed in options $A$,$B$,or $C$,the correct answer is $D$.

List-$I$	List-$II$
$A$. $H_3O^+$	$I$. Tetrahedral
$B$. Acetylide anion	$II$. Linear
$C$. $NH_4^+$	$III$. Pyramidal
$D$. $ClO_2^-$	$IV$. Bent

The increasing order of $O-N-O$ bond angle in the species $NO_2$,$NO_2^+$ and $NO_2^-$ is

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Match List-$I$ with List-$II$ :

List-$I$ List-$II$

$A$. $H_3O^+$ $I$. Tetrahedral

$B$. Acetylide anion $II$. Linear

$C$. $NH_4^+$ $III$. Pyramidal

$D$. $ClO_2^-$ $IV$. Bent

Choose the correct answer from the options given below :

Explain: The geometry of $NH_3$ molecule is trigonal pyramidal.

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