The increasing order of pH of 0.1 M solution | vedclass

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(D) $HCl$ is a strong acid $(SA)$,so its $pH$ is very low (approx $1$).$NH_4NO_3$ is a salt of a strong acid and a weak base $(SAWB)$,which undergoes

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$HCl < NH_4NO_3 < NaCl < NaCN$

Vedclass · Answer

(D) $HCl$ is a strong acid $(SA)$,so its $pH$ is very low (approx $1$).$NH_4NO_3$ is a salt of a strong acid and a weak base $(SAWB)$,which undergoes cationic hydrolysis,making the solution acidic $(pH $NaCl$ is a salt of a strong acid and a strong base $(SASB)$,which does not undergo hydrolysis,making the solution neutral $(pH = 7)$.$NaCN$ is a salt of a weak acid and a strong base $(WASB)$,which undergoes anionic hydrolysis,making the solution basic $(pH > 7)$.Therefore,the increasing order of $pH$ is $HCl < NH_4NO_3 < NaCl < NaCN$.

The increasing order of $pH$ of $0.1 \ M$ solution of the following compounds is:

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