The incorrect statement(s) among (a)-(c) is ( | vedclass

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(D) $W(VI)$ (tungsten in $+6$ oxidation state) is indeed more stable than $Cr(VI)$ (chromium in $+6$ oxidation state) because stability increases down

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$(b)$ only

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(D) $W(VI)$ (tungsten in $+6$ oxidation state) is indeed more stable than $Cr(VI)$ (chromium in $+6$ oxidation state) because stability increases down the group in group $6$ elements.$(b)$ $KMnO_4$ is a strong oxidizing agent. In the presence of $HCl$,$KMnO_4$ oxidizes $HCl$ to $Cl_2$ gas. Therefore,$HCl$ cannot be used in permanganate titrations as it interferes with the reaction,making the results unsatisfactory.$(c)$ Lanthanoid oxides (e.g.,$Y_2O_3$ doped with $Eu$) are widely used as phosphors in television screens and fluorescent lamps.Thus,only statement $(b)$ is incorrect.

The incorrect statement$(s)$ among $(a)-(c)$ is (are) :-
$(a)$ $W(VI)$ is more stable than $Cr(VI)$
$(b)$ In the presence of $HCl$,permanganate titrations provide satisfactory results.
$(c)$ Some lanthanoid oxides can be used as phosphors.

Similar Questions

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The incorrect statement$(s)$ among $(a)-(c)$ is (are) :-$(a)$ $W(VI)$ is more stable than $Cr(VI)$$(b)$ In the presence of $HCl$,permanganate titrations provide satisfactory results.$(c)$ Some lanthanoid oxides can be used as phosphors.