The incorrect statement regarding the reactio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of $N,N$-dimethylaniline with $NaNO_2$ and $HX$ (nitrous acid) at low temperature $(0-5^{\circ}C)$ is an electrophilic aromatic subst

Vedclass · Accepted Answer

$'B'$ is $N$-nitroso ammonium compound

Vedclass · Answer

(B) The reaction of $N,N$-dimethylaniline with $NaNO_2$ and $HX$ (nitrous acid) at low temperature $(0-5^{\circ}C)$ is an electrophilic aromatic substitution reaction.$1$. The electrophile generated is the nitrosonium ion,$NO^{+}$.$2$. Since the $-N(CH_3)_2$ group is a strong ortho/para directing group,the electrophile $NO^{+}$ attacks the para position to form $p$-nitroso-$N,N$-dimethylaniline.$3$. Option $A$ is correct as $NO^{+}$ is the electrophile.$4$. Option $B$ is incorrect because the product is $p$-nitroso-$N,N$-dimethylaniline,not an $N$-nitroso ammonium compound (which would form with secondary amines).$5$. Option $C$ is correct as the reaction is performed at low temperatures to stabilize the nitrous acid and prevent side reactions.$6$. Option $D$ is correct as the major product is the $p$-nitroso derivative.

The incorrect statement regarding the reaction given below is:

Similar Questions

In the reaction shown,the structure of the product $T$ is:

How will you carry out the following conversion?
$Aniline \rightarrow m-Bromonitrobenzene$

Consider the following reaction:
$C_6H_5NO_2$ $\xrightarrow{Sn / HCl} X$ $\xrightarrow{C_6H_5COCl} Y + HCl$
What is $Y$?

The correct order of basic strength is:

Which of the following has the highest value of $pK_b$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module