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(B) The reactions are as follows:$1. \ Al + 6HCl(aq.) \rightarrow 2AlCl_3 + 3H_2(g) \uparrow$ (Gas $P$ is $H_2$)$2. \ 2Al + 2NaOH(aq.) + 6H_2O \righta

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Gas '$P$' and '$Q$' are different

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(B) The reactions are as follows:$1. \ Al + 6HCl(aq.) \rightarrow 2AlCl_3 + 3H_2(g) \uparrow$ (Gas $P$ is $H_2$)$2. \ 2Al + 2NaOH(aq.) + 6H_2O \rightarrow 2Na[Al(OH)_4] + 3H_2(g) \uparrow$ (Gas $Q$ is $H_2$)Comparing the products:- Gas $P$ and $Q$ are both $H_2$,so they are the same.- $X$ $(AlCl_3)$ and $Y$ $(Na[Al(OH)_4])$ are both water-soluble.- $Al$ is amphoteric as it reacts with both acids and bases.- $H_2$ gas is inflammable.Therefore,the statement 'Gas $P$ and $Q$ are different' is incorrect.

The incorrect statement regarding the above reactions is:
$Al \xrightarrow{HCl(aq.)} 'X' + \text{Gas } 'P'$
$Al \xrightarrow{NaOH(aq.) + H_2O} 'Y' + \text{Gas } 'Q'$

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The incorrect statement regarding the above reactions is:$Al \xrightarrow{HCl(aq.)} 'X' + \text{Gas } 'P'$$Al \xrightarrow{NaOH(aq.) + H_2O} 'Y' + \text{Gas } 'Q'$