The hydration energies of K^{+} and Cl^{-} ar | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the Born-Haber cycle for the dissolution of an ionic solid,the heat of solution $(\Delta H_{sol})$ is the sum of the lattice energy $

Vedclass · Accepted Answer

$z-(x+y)$

Vedclass · Answer

(C) According to the Born-Haber cycle for the dissolution of an ionic solid,the heat of solution $(\Delta H_{sol})$ is the sum of the lattice energy $(L.E.)$ and the hydration energies $(H.E.)$ of the constituent ions.$\Delta H_{sol} = L.E. + (H.E.)_{K^{+}} + (H.E.)_{Cl^{-}}$Given:$L.E. = -z \ kJ / mol$$(H.E.)_{K^{+}} = -x \ kJ / mol$$(H.E.)_{Cl^{-}} = -y \ kJ / mol$Substituting these values into the equation:$\Delta H_{sol} = (-z) + (-x) + (-y)$$\Delta H_{sol} = -z - x - y$$\Delta H_{sol} = -(z + x + y)$Wait,let us re-evaluate the standard definition. Usually,$L.E.$ is defined as the energy released when gaseous ions form a solid,so $L.E. = +z$ (energy required to break the lattice). If $L.E.$ is given as $-z$ (energy released),then the energy to break the lattice is $+z$.Thus,$\Delta H_{sol} = z + (-x) + (-y) = z - (x + y)$.

The hydration energies of $K^{+}$ and $Cl^{-}$ are $-x$ and $-y$ $kJ / mol$ respectively. If the lattice energy of $KCl$ is $-z$ $kJ / mol$,then the heat of solution of $KCl$ is $:$

Similar Questions

Solid $PCl_5$ exists as $:$

Arrange the following forces in the increasing order of their interaction energy:
London forces,Covalent bond,Hydrogen bond,Dipole-dipole forces

The number of network solids and ionic solids in the list given below is respectively $H_2O$ (ice),$AlN$,$Cu$,$CaF_2$,diamond,$MgO$,$CCl_4$,$ZnS$,$Ag$,$NaCl$,$SiO_2$.

Which among the following forces of attraction is developed between polar and non-polar molecules?

Explain dipole-induced dipole forces.

Vedclass Test Series

Exam Paper Generator

Online Exam Module