The hybridisation involved in $[CoF_6]^{3-}$ is :

Given below are two statements:
Statement $I$: $[Mn(CN)_6]^{3-}$,$[Fe(CN)_6]^{3-}$ and $[Co(C_2O_4)_3]^{3-}$ are $d^2sp^3$ hybridized.
Statement $II$: $[MnCl_6]^{3-}$ and $[FeF_6]^{3-}$ are paramagnetic and have $4$ and $5$ unpaired electrons,respectively.
In the light of the above statements,choose the correct answer from the options given below:

In the complex $[SbF_5]^{2-}$,$sp^3d$ hybridisation is present. The geometry of the complex is:

In aqueous solution,$[Co(H_2O)_6]^{2+} (X)$ reacts with molecular oxygen in the presence of excess liquor $NH_3$ to give a new complex $Y$. The number of unpaired electrons in $X$ and $Y$ are,respectively:

Explain why $[Co(NH_{3})_{6}]^{3+}$ is an inner orbital complex whereas $[Ni(NH_{3})_{6}]^{2+}$ is an outer orbital complex.

The number of unpaired electrons in $[Co(NH_3)_6]^{3+}$ and $[CoF_6]^{3-}$ are respectively.....