The hybridization of IF_7 is | vedclass

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(A) The central atom $I$ (Iodine) has the valence shell electronic configuration $5s^2 5p^5$.In the excited state,$I$ promotes electrons to the $5d$ o

Vedclass · Accepted Answer

$sp^3d^3$

Vedclass · Answer

(A) The central atom $I$ (Iodine) has the valence shell electronic configuration $5s^2 5p^5$.In the excited state,$I$ promotes electrons to the $5d$ orbitals to form $7$ unpaired electrons to bond with $7$ fluorine atoms.This results in the involvement of one $s$,three $p$,and three $d$ orbitals,leading to $sp^3d^3$ hybridization.Therefore,the hybridization of $IF_7$ is $sp^3d^3$,and its geometry is pentagonal bipyramidal.

The hybridization of $IF_7$ is

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