The horizontal and vertical displacements x a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given,$x = 6t$ and $y = 8t - 5t^2$.Comparing these with the standard equations of projectile motion:$x = (u \cos 	heta)t \implies u \cos 	heta =

Vedclass · Accepted Answer

$9.6$

Vedclass · Answer

(A) Given,$x = 6t$ and $y = 8t - 5t^2$.Comparing these with the standard equations of projectile motion:$x = (u \cos 	heta)t \implies u \cos 	heta = 6 	ext{ m/s}$.$y = (u \sin 	heta)t - \frac{1}{2}gt^2 = 8t - 5t^2$.Comparing the coefficients,we get $u \sin 	heta = 8 	ext{ m/s}$ and $\frac{1}{2}g = 5$,which implies $g = 10 	ext{ m/s}^2$.The range $R$ of a projectile is given by the formula:$R = \frac{u^2 \sin 2	heta}{g} = \frac{2(u \sin 	heta)(u \cos 	heta)}{g}$.Substituting the values:$R = \frac{2 	imes 8 	imes 6}{10} = \frac{96}{10} = 9.6 	ext{ m}$.

The horizontal and vertical displacements $x$ and $y$ of a projectile at a given time $t$ are given by $x = 6t \text{ m}$ and $y = 8t - 5t^2 \text{ m}$. The range of the projectile in metres is

Similar Questions

It is now possible to breed plants and animals with desired characters through:

The component of vector $\overrightarrow{A} = a_x \hat{i} + a_y \hat{j} + a_z \hat{k}$ along the direction of $\hat{i} - \hat{j}$ is

What is $Z$ in the following reaction sequence?
$C_6H_5NH_2$ $\xrightarrow[(i) NaNO_2 + HCl / 273 \ K]{(ii) H_3PO_2 + H_2O}$ $\xrightarrow[(iii) CO, HCl, \text{anhydrous } AlCl_3/CuCl]{} Z$

The cubic equation whose roots are thrice to each of the roots of $x^3+2 x^2-4 x+1=0$ is

If a line $l$ passes through $(k, 2k), (3k, 3k)$ and $(3, 1)$ where $k \neq 0$,then the distance from the origin to the line $l$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module