The half-life period of a radioactive materia | vedclass

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(B) The number of half-lives $n$ is calculated as $n = \frac{	ext{Total time}}{	ext{Half-life}} = \frac{45 \ min}{15 \ min} = 3$. The remaining amou

Vedclass · Accepted Answer

$12.5$

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(B) The number of half-lives $n$ is calculated as $n = \frac{	ext{Total time}}{	ext{Half-life}} = \frac{45 \ min}{15 \ min} = 3$. The remaining amount of radioactive material $N$ is given by the formula $N = N_o 	imes (\frac{1}{2})^n$. Assuming the initial amount $N_o = 100 \%$,the remaining amount is $N = 100 	imes (\frac{1}{2})^3 = \frac{100}{8} = 12.5 \%$. Thus,$12.5 \%$ of the radioactivity remains.

The half-life period of a radioactive material is $15 \ minutes$. What $\%$ of radioactivity of that material will remain after $45 \ minutes$?

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