The half-life period for a certain zero-order | vedclass

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Question

(A) For a zero-order reaction, the rate constant $k$ is related to the half-life $t_{1/2}$ by the formula $t_{1/2} = \frac{[A]_0}{2k}$.
Given $t_{1/2

Vedclass · Accepted Answer

$20$

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(A) For a zero-order reaction, the rate constant $k$ is related to the half-life $t_{1/2}$ by the formula $t_{1/2} = \frac{[A]_0}{2k}$.
Given $t_{1/2} = 10 	ext{ min}$, we can find the initial concentration in terms of $k$: $[A]_0 = 2k 	imes t_{1/2} = 2k 	imes 10 = 20k$.
The time required to complete the reaction $(100\%)$ is given by the formula $t_{100\%} = \frac{[A]_0}{k}$.
Substituting the value of $[A]_0$, we get $t_{100\%} = \frac{20k}{k} = 20 	ext{ min}$.
Therefore, the reaction completes in $20 	ext{ minutes}$.

The half-life period for a certain zero-order reaction is $10 \text{ min}$. How much time is required for this reaction to complete $100\%$ (in $\text{ min}$)?

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