(B) The number of half-lives $n$ is given by $n = \frac{t}{T_{1/2}}$.Given $t = 40 \ h$ and $T_{1/2} = 10 \ h$,we have $n = \frac{40}{10} = 4$.The rem

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(B) The number of half-lives $n$ is given by $n = \frac{t}{T_{1/2}}$.Given $t = 40 \ h$ and $T_{1/2} = 10 \ h$,we have $n = \frac{40}{10} = 4$.The remaining fraction of the initial radioactivity is given by $\frac{N}{N_0} = (\frac{1}{2})^n$.Substituting $n = 4$,we get $\frac{N}{N_0} = (\frac{1}{2})^4 = \frac{1}{16}$.

Class 12 Physics Nuclei Law of Radioactivity by Rutherford and Soddy and Half Life and Mean Life

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The half-life of a radioactive element is $10 \ h$. The fraction of initial radioactivity of the element that will remain after $40 \ h$ is

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A
$\frac{1}{2}$
B
$\frac{1}{16}$
C
$\frac{1}{8}$
D
$\frac{1}{4}$

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Law of Radioactivity by Rutherford and Soddy and Half Life and Mean Life

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The half-life of a radioactive element is $10 \ h$. The fraction of initial radioactivity of the element that will remain after $40 \ h$ is

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