The gravitational force between two objects i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Newton's law of universal gravitation,the force $F$ between two objects of masses $m_1$ and $m_2$ separated by a distance $r$ is give

Vedclass · Accepted Answer

$F/4$

Vedclass · Answer

(C) According to Newton's law of universal gravitation,the force $F$ between two objects of masses $m_1$ and $m_2$ separated by a distance $r$ is given by $F = G \frac{m_1 m_2}{r^2}$.When the masses of both objects are halved,the new masses become $m_1' = \frac{m_1}{2}$ and $m_2' = \frac{m_2}{2}$.The new gravitational force $F'$ is $F' = G \frac{(\frac{m_1}{2})(\frac{m_2}{2})}{r^2} = G \frac{m_1 m_2}{4r^2} = \frac{1}{4} F$.Therefore,the gravitational force becomes $F/4$.

The gravitational force between two objects is $F$. If the masses of both objects are halved without changing the distance between them,then the gravitational force would become:

Similar Questions

$A$ stone is released from the top of a tower of height $19.6 \, m$. Calculate its velocity just before touching the ground.

Earth is continuously pulling the moon towards its centre,still it does not fall to the earth,why?

In vacuum,all freely falling objects:

The value of acceleration due to gravity

Vedclass Test Series

Exam Paper Generator

Online Exam Module