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(C) From the graph,the substance undergoes a phase change (vaporization) at a constant temperature of $125^{\circ} C$. This phase change occurs from $

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$84$

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(C) From the graph,the substance undergoes a phase change (vaporization) at a constant temperature of $125^{\circ} C$. This phase change occurs from $t = 20 \, min$ to $t = 30 \, min$.The duration of the vaporization process is $\Delta t = 30 - 20 = 10 \, min$.The rate of heat absorption is $P = 42 \, kJ \, min^{-1}$.The total heat absorbed during vaporization is $Q = P 	imes \Delta t = 42 	imes 10 = 420 \, kJ$.The mass of the substance is $m = 5 \, kg$.The latent heat of vaporization $L$ is given by $Q = m 	imes L$.Therefore,$L = \frac{Q}{m} = \frac{420}{5} = 84 \, kJ \, kg^{-1}$.

The graph shown in the figure represents the change in the temperature of $5 \, kg$ of a substance as it absorbs heat at a constant rate of $42 \, kJ \, min^{-1}$. The latent heat of vaporization of the substance is ......... $kJ \, kg^{-1}$.

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