The graph of the equation x+y=11 passes throu | vedclass

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Question

(B) The equation is $x+y=11$.
To find the quadrants,we check the intercepts:
If $x=0$,then $y=11$. The point is $(0, 11)$,which lies on the $y$-axis

Vedclass · Accepted Answer

fourth and second quadrants

Vedclass · Answer

(B) The equation is $x+y=11$. To find the quadrants,we check the intercepts: If $x=0$,then $y=11$. The point is $(0, 11)$,which lies on the $y$-axis between the first and second quadrants. If $y=0$,then $x=11$. The point is $(11, 0)$,which lies on the $x$-axis between the first and fourth quadrants. Since the line passes through $(0, 11)$ and $(11, 0)$,it passes through the first quadrant (where $x>0, y>0$),the second quadrant (where $x<0, y>0$ for $x < 0$),and the fourth quadrant (where $x>0, y<0$ for $x > 11$). Thus,the line passes through the second,first,and fourth quadrants.

$x$	$0$	$1$	$2$	$3$	$4$
$y$	$2$	$3$	$4$	$-5$	$6$

The graph of the equation $x+y=11$ passes through the first quadrant and .............

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