The graph given below is the distance$-$time graph of an object.
$(i)$ Find the speed of the object during first four seconds of its journey.
$(ii)$ How long was it stationary ?
$(iii)$ Does it represent a real life situation ? Justify your answer.
$(i)$ $\frac{(75-0)}{(4-0)}=\frac{75}{4}=18.75 m s ^{-1}$
$(ii)$ $(14-4)=10 s$
$(iii)$ No as distance cannot decrease with time.
Explain the following type of motion with one example of each
$(i)$ Acceleration is positive
$(ii)$ Acceleration is negative
$(iii)$ Acceleration is zero.
What is the relationship between the distance travelled and the time elapsed for motion with uniform velocity ?
Two graphs for motion of objects moving along a straight line are shown. State how the speed is changing with time in both cases.
The velocity$-$time graph of a car is given below. The car weighs $1000\, kg$.
$(i)$ What is the distance travelled by the car in the first $2$ seconds ?
$(ii)$ What is the braking force at the end of $5$ seconds to bring the car to a stop within one second ?
What conclusion can you draw from the displacement$-$time graph of a body as shown below ?