The given graph shows the displacement versus | vedclass

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Question

(A) From the graph,the time period $T$ is the time taken for one complete oscillation. Looking at the graph,one complete wave cycle spans from $t = 0.

Vedclass · Accepted Answer

$3 	imes 10^{-3} \, m$

Vedclass · Answer

(A) From the graph,the time period $T$ is the time taken for one complete oscillation. Looking at the graph,one complete wave cycle spans from $t = 0.5 \, \mu s$ to $t = 2.5 \, \mu s$ (or similar interval),which gives $T = 2 \, \mu s = 2 	imes 10^{-6} \, s$. Frequency $f = 1/T = 1 / (2 	imes 10^{-6} \, s) = 0.5 	imes 10^6 \, Hz = 5 	imes 10^5 \, Hz$. Given velocity $v = 1500 \, m \, s^{-1}$. Wavelength $\lambda = v / f = 1500 / (5 	imes 10^5) = 300 	imes 10^{-5} \, m = 3 	imes 10^{-3} \, m$.

The given graph shows the displacement versus time relation for a disturbance travelling with a velocity of $1500\, m \,s^{-1}$. Calculate the wavelength of the disturbance.

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