The geometry of the molecule with sp^3d^2 hyb | vedclass

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(C) The hybridization of a central atom is determined by the number of electron pairs (bonding pairs + lone pairs) around it.For $sp^3d^2$ hybridizati

Vedclass · Accepted Answer

Octahedral

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(C) The hybridization of a central atom is determined by the number of electron pairs (bonding pairs + lone pairs) around it.For $sp^3d^2$ hybridization,the number of hybrid orbitals is $1 + 3 + 2 = 6$.According to the Valence Shell Electron Pair Repulsion $(VSEPR)$ theory,a molecule with $6$ electron pairs arranged around a central atom adopts an octahedral geometry to minimize inter-electronic repulsions.Therefore,the geometry of the molecule with $sp^3d^2$ hybridized central atom is octahedral.

	Molecule	Hybridization	Geometry	Number of lone pairs of electrons on central atom
$I$	$SiH_4$	$sp^3$	tetrahedral	$0$
$II$	$BeCl_2$	$sp^2$	linear	$1$
$III$	$SF_4$	$dsp^3$	square planar	$1$
$IV$	$SnCl_2$	$sp$	linear	$0$

The geometry of the molecule with $sp^3d^2$ hybridised central atom is

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Molecule Hybridization Geometry Number of lone pairs of electrons on central atom
$I$ $SiH_4$ $sp^3$ tetrahedral $0$
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$III$ $SF_4$ $dsp^3$ square planar $1$
$IV$ $SnCl_2$ $sp$ linear $0$

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