The fusion of chromite ore $(FeCr_{2}O_{4})$ with $Na_{2}CO_{3}$ in air gives a yellow solution upon addition of water. Subsequent treatment with $H_{2}SO_{4}$ produces an orange solution. The yellow and orange colours,respectively,are due to the formation of

  • A
    $Na_{2}CrO_{4}$ and $Na_{2}Cr_{2}O_{7}$
  • B
    $Cr(OH)_{3}$ and $Na_{2}Cr_{2}O_{7}$
  • C
    $Cr_{2}(CO_{3})_{3}$ and $Fe_{2}(SO_{4})_{3}$
  • D
    $Cr(OH)_{3}$ and $Na_{2}CrO_{4}$

Explore More

Similar Questions

In ruby and emerald,the metal ion$(s)$ present is/are

Which of the following is a product of the first step and is used as a reactant in the next step for the manufacture of $K_{2}Cr_{2}O_{7}$ from concentrated chromite ore?

When a mixture of manganese dioxide,potassium hydroxide and potassium chlorate is fused,the product obtained is

$A$ blue borax bead is obtained with:

The oxoanion which contains all equivalent $M-O$ bonds is:
$(I)$ $CrO_4^{2-}$
$(II)$ $MnO_4^-$
$(III)$ $Cr_2O_7^{2-}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo