The function sin^2(omega t) represents | vedclass

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(D) We know that $\sin^2(\omega t) = \frac{1 - \cos(2\omega t)}{2} = \frac{1}{2} - \frac{1}{2}\cos(2\omega t)$.This expression represents a simple har

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a simple harmonic motion with a period $\pi /\omega$

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(D) We know that $\sin^2(\omega t) = \frac{1 - \cos(2\omega t)}{2} = \frac{1}{2} - \frac{1}{2}\cos(2\omega t)$.This expression represents a simple harmonic motion $(SHM)$ because it is of the form $y = A + B\cos(\omega' t)$,where $A$ and $B$ are constants.The angular frequency of this motion is $\omega' = 2\omega$.The time period $T$ is given by $T = \frac{2\pi}{\omega'} = \frac{2\pi}{2\omega} = \frac{\pi}{\omega}$.Therefore,the function represents a simple harmonic motion with a period $\pi /\omega$.

The function $\sin^2(\omega t)$ represents

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