The frequencies of K_{alpha},K_{beta},and L_{ | vedclass

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Question

(B) In an atom,the energy levels are defined such that the energy of the $K_{\beta}$ transition is equal to the sum of the energies of the $K_{\alpha}

Vedclass · Accepted Answer

$
u_2 = 
u_1 + 
u_3$

Vedclass · Answer

(B) In an atom,the energy levels are defined such that the energy of the $K_{\beta}$ transition is equal to the sum of the energies of the $K_{\alpha}$ and $L_{\alpha}$ transitions.Since the energy of a photon is given by $E = h
u$,we have:$E(K_{\beta}) = E(K_{\alpha}) + E(L_{\alpha})$Substituting the frequency relations:$h
u_2 = h
u_1 + h
u_3$Dividing by $h$,we get:$
u_2 = 
u_1 + 
u_3$

The frequencies of $K_{\alpha}$,$K_{\beta}$,and $L_{\alpha}$ $X$-rays of a material are $\nu_1$,$\nu_2$,and $\nu_3$ respectively. Which of the following relations holds good?

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