The freezing point of equimolal aqueous solut | vedclass

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(D) The depression in freezing point is given by the formula $\Delta T_f = i K_f m$. Since the solutions are equimolal,$K_f$ and $m$ are constant. Thu

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$C_6H_{12}O_6$

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(D) The depression in freezing point is given by the formula $\Delta T_f = i K_f m$. Since the solutions are equimolal,$K_f$ and $m$ are constant. Thus,$\Delta T_f \propto i$,where $i$ is the van't Hoff factor. Freezing point $T_f = T_f^{\circ} - \Delta T_f$. To have the highest freezing point,the depression in freezing point $\Delta T_f$ must be the minimum,which means $i$ must be the minimum. For the given substances: $C_6H_5NH_3Cl \rightarrow C_6H_5NH_3^+ + Cl^-$ $(i = 2)$ $Ba(NO_3)_2 \rightarrow Ba^{2+} + 2NO_3^-$ $(i = 3)$ $LaCl_3 \rightarrow La^{3+} + 3Cl^-$ $(i = 4)$ $C_6H_{12}O_6$ is a non-electrolyte and does not dissociate $(i = 1)$. Since $C_6H_{12}O_6$ has the lowest $i$ value,it will have the minimum $\Delta T_f$ and consequently the highest freezing point.

The freezing point of equimolal aqueous solution will be highest for

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