The four quantum numbers for the electron in | vedclass

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(B) The electronic configuration of potassium $(Z=19)$ is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^1$.The outermost electron enters the $4s$ orbital.For the

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$n=4, l=0, m=0, s=+\frac{1}{2}$

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(B) The electronic configuration of potassium $(Z=19)$ is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^1$.The outermost electron enters the $4s$ orbital.For the $4s$ orbital,the principal quantum number $n=4$.Since it is an $s$-orbital,the azimuthal quantum number $l=0$.Consequently,the magnetic quantum number $m=0$.The spin quantum number $s$ can be $+\frac{1}{2}$ or $-\frac{1}{2}$.Comparing this with the given options,option $B$ is correct.

The four quantum numbers for the electron in the outermost orbital of potassium (atomic number $19$) are:

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