The formula of the complex hydridotrimethoxyb | vedclass

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Question

(C) The complex hydridotrimethoxyborate$(III)$ ion consists of one hydride ion $(H^-)$ and three methoxide ions $(OCH_3^-)$ coordinated to a central b

Vedclass · Accepted Answer

$[BH(OCH_3)_3]^-$

Vedclass · Answer

(C) The complex hydridotrimethoxyborate$(III)$ ion consists of one hydride ion $(H^-)$ and three methoxide ions $(OCH_3^-)$ coordinated to a central boron atom $(B)$.The oxidation state of boron is given as $+3$.Let the oxidation state of boron be $x$.The sum of oxidation states in the complex is equal to the charge on the ion $(n)$:$x + (1 	imes -1) + (3 	imes -1) = n$$x - 1 - 3 = n$$x - 4 = n$Given that the oxidation state of boron $(x)$ is $+3$:$3 - 4 = n$$n = -1$Therefore,the charge on the complex ion is $-1$,and the formula is $[BH(OCH_3)_3]^-$.Thus,option $C$ is correct.

The formula of the complex hydridotrimethoxyborate$(III)$ ion is:

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