The formula of potassium dicyanobis(oxalato)n | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the formula,we analyze the components of the name:$1$. The central metal is nickel $(Ni)$ with an oxidation state of $+II$.$2$. The l

Vedclass · Accepted Answer

$K_4[Ni(CN)_2(C_2O_4)_2]$

Vedclass · Answer

(A) To determine the formula,we analyze the components of the name:$1$. The central metal is nickel $(Ni)$ with an oxidation state of $+II$.$2$. The ligands are two cyano groups $(CN^-)$ and two oxalato groups $(C_2O_4^{2-})$.$3$. The coordination sphere charge is calculated as: $x = (+2) + 2(-1) + 2(-2) = 2 - 2 - 4 = -4$.$4$. To balance the charge of $-4$,we need four potassium ions $(K^+)$.$5$. Thus,the formula is $K_4[Ni(CN)_2(C_2O_4)_2]$.

The formula of potassium dicyanobis(oxalato)nickelate$(II)$ is

Similar Questions

State the $IUPAC$ name of the following complex: Nessler's reagent.

$K_2[Zn(OH)_4]$ is the chemical formula for which coordination compound?

The oxidation number of $Co$ in the complex ion $[(en)_2Co(\mu-NH_2)(\mu-OH)Co(en)_2]^{3+}$ is:

In ammonium phosphomolybdate,the oxidation state of $Mo$ is $..........$.

What is the oxidation number of $Fe$ in $K_3[Fe(CN)_6]$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module