The formula for calculating 'spin only' magnetic moment is
- A$n(n+2)$
- B$\sqrt{n(n-2)}$
- C$\sqrt{n(n+2)}$
- D$n(n-2)$
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Similar Questions
Consider the following isomerisms:
$1.$ Ionization
$2.$ Hydrate
$3.$ Linkage
$4.$ Geometrical
$5.$ Optical
Which isomerisms are exhibited by $[Cr(NH_3)_2(OH)_2Cl_2]^-$?
$1.$ Ionization
$2.$ Hydrate
$3.$ Linkage
$4.$ Geometrical
$5.$ Optical
Which isomerisms are exhibited by $[Cr(NH_3)_2(OH)_2Cl_2]^-$?
Difficult
View SolutionWhich of the following complexes has a zero magnetic moment (spin only)?
MediumAIIMS 2009
View SolutionDraw all the isomers (geometrical and optical) of:
$(i)$ $[CoCl_2(en)_2]^+$
$(ii)$ $[Co(NH_3)Cl(en)_2]^{2+}$
$(iii)$ $[Co(NH_3)_2Cl_2(en)]^+$
$(i)$ $[CoCl_2(en)_2]^+$
$(ii)$ $[Co(NH_3)Cl(en)_2]^{2+}$
$(iii)$ $[Co(NH_3)_2Cl_2(en)]^+$
Medium
View SolutionWhich of the following is a chiral complex? Here $en = \text{ethylenediamine}$.
The complex compounds $[Co(NH_3)_5 SO_4] Br$ and $[Co(NH_3)_5 Br] SO_4$ are
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