Easy
The formation of $SO_3$ takes place according to the following reaction: $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$; $\Delta H = -45.2 \ kcal$. The formation of $SO_3$ is favoured by:
- AIncreasing the temperature
- BRemoval of oxygen
- CIncrease in volume
- DIncreasing the pressure
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Consider the given endothermic reaction at equilibrium,$PCl_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)}$. $A$ graph is plotted between concentration and time as shown. Effect-$1$ and Effect-$2$ are due to respectively:
Medium
View SolutionState Le Chatelier's Principle.
Medium
View SolutionExplain the effect of adding $(i)$ Oxalic acid $(H_2C_2O_4)$,$(ii)$ $HgCl_2$,and $(iii)$ Potassium thiocyanate $(KSCN)$ on the equilibrium reaction: $Fe^{3+}(aq) + SCN^-(aq) \rightleftharpoons [Fe(SCN)]^{2+}(aq)$ (deep red color).
Difficult
View Solution$2x_{(g)} + y_{(g)} \rightleftarrows 2z_{(g)} + 80 \ kcal$
Which combination gives the highest yield of $z$ at equilibrium?
Which combination gives the highest yield of $z$ at equilibrium?
Medium
View SolutionWhen $I_2$ dissociates to its atomic form the following reaction occurs:
$I_{2(g)} \rightleftharpoons 2I_{(g)} ; \Delta_r H^o = +150 \ kJ \ mol^{-1}$
The forward reaction is favoured at:
$I_{2(g)} \rightleftharpoons 2I_{(g)} ; \Delta_r H^o = +150 \ kJ \ mol^{-1}$
The forward reaction is favoured at:
Easy
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