(D) $PH_3 + H^+ \to PH_4^+$According to Drago's rule,the lone pair on phosphorus resides in an almost pure $s-$ orbital.Due to the non-directional nat

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lone pair of phosphorus resides in almost pure $s-$ orbital

(D) $PH_3 + H^+ \to PH_4^+$According to Drago's rule,the lone pair on phosphorus resides in an almost pure $s-$ orbital.Due to the non-directional nature of the $s-$ orbital,its overlapping tendency with the $H^+$ ion is greatly reduced compared to the lone pair in $NH_3$,which resides in a directional $sp^3$ hybrid orbital.

Class 11 Chemistry Chemical Bonding and Molecular Structure Mix Examples-Chemical Bonding

The formation of $PH_4^+$ is difficult compared to $NH_4^+$ because

A
lone pair of phosphorus is optically inert
B
lone pair of phosphorus resides in almost pure $p-$ orbital
C
lone pair of phosphorus resides at $sp^3$ orbital
D
lone pair of phosphorus resides in almost pure $s-$ orbital

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Class 11

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Chemical Bonding and Molecular Structure

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Mix Examples-Chemical Bonding

Compare the $x$ and $y$ bond lengths in the following molecules:
Structure $1$: $HO-S(=O)-S(=O)-OH$ (where $x$ is the $S-S$ bond length)
Structure $2$: $HO-S(=O)_2-S(=O)-OH$ (where $y$ is the $S-S$ bond length)

Medium

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Born-Haber cycle may be used to calculate:
$I$. $\Delta_{eg}H$
$II$. Mass number
$III$. Electronegativity
$IV$. Lattice energy

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The name of $K_2CS_3$ is potassium ............... .

Easy

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Which of the following has been arranged in order of decreasing bond dissociation energy:

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Choose the incorrect order of bond length $-$

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The formation of $PH_4^+$ is difficult compared to $NH_4^+$ because

Similar Questions

Compare the $x$ and $y$ bond lengths in the following molecules:Structure $1$: $HO-S(=O)-S(=O)-OH$ (where $x$ is the $S-S$ bond length)Structure $2$: $HO-S(=O)_2-S(=O)-OH$ (where $y$ is the $S-S$ bond length)

Born-Haber cycle may be used to calculate:$I$. $\Delta_{eg}H$$II$. Mass number$III$. Electronegativity$IV$. Lattice energy

The name of $K_2CS_3$ is potassium ............... .

Which of the following has been arranged in order of decreasing bond dissociation energy:

Choose the incorrect order of bond length $-$

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Compare the $x$ and $y$ bond lengths in the following molecules:
Structure $1$: $HO-S(=O)-S(=O)-OH$ (where $x$ is the $S-S$ bond length)
Structure $2$: $HO-S(=O)_2-S(=O)-OH$ (where $y$ is the $S-S$ bond length)

Born-Haber cycle may be used to calculate:
$I$. $\Delta_{eg}H$
$II$. Mass number
$III$. Electronegativity
$IV$. Lattice energy