The force required to separate two glass plat | vedclass

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(A) The force $F$ required to separate two plates of area $A$ separated by a liquid film of thickness $t$ and surface tension $T$ is given by the form

Vedclass · Accepted Answer

$28$

Vedclass · Answer

(A) The force $F$ required to separate two plates of area $A$ separated by a liquid film of thickness $t$ and surface tension $T$ is given by the formula:$F = \frac{2TA}{t}$Given:Area $A = 10^{-2} \, m^2$Thickness $t = 0.05 \, mm = 0.05 	imes 10^{-3} \, m$Surface tension $T = 70 	imes 10^{-3} \, N/m$Substituting the values:$F = \frac{2 	imes (70 	imes 10^{-3}) 	imes 10^{-2}}{0.05 	imes 10^{-3}}$$F = \frac{140 	imes 10^{-5}}{0.05 	imes 10^{-3}}$$F = \frac{140}{0.05} 	imes 10^{-2} = 2800 	imes 10^{-2} = 28 \, N$Therefore,the correct option is $A$.

The force required to separate two glass plates of area $10^{-2} \, m^2$ with a film of water $0.05 \, mm$ thick between them is ...... $N$. (Surface tension of water is $70 \times 10^{-3} \, N/m$)

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