The following truth table with A and B as inp | vedclass

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(D) Let us analyze the truth table provided:$1$. When $A=1, B=0$,Output = $1$.$2$. When $A=1, B=1$,Output = $0$.$3$. When $A=0, B=1$,Output = $1$.$4$.

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$XOR$

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(D) Let us analyze the truth table provided:$1$. When $A=1, B=0$,Output = $1$.$2$. When $A=1, B=1$,Output = $0$.$3$. When $A=0, B=1$,Output = $1$.$4$. When $A=0, B=0$,Output = $0$.Comparing this with standard logic gates:- For an $XOR$ gate,the output is $1$ only when the inputs are different $(A 
eq B)$.- In this table,the output is $1$ when $(A=1, B=0)$ or $(A=0, B=1)$,and $0$ when $(A=1, B=1)$ or $(A=0, B=0)$.- This behavior perfectly matches the $XOR$ gate (Exclusive-$OR$ gate),which follows the Boolean expression $Y = A \oplus B$.

The following truth table with $A$ and $B$ as inputs is for which logic gate?
$A$ $B$ Output
$1$ $0$ $1$
$1$ $1$ $0$
$0$ $1$ $1$
$0$ $0$ $0$

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The following truth table with $A$ and $B$ as inputs is for which logic gate?$A$$B$Output$1$$0$$1$$1$$1$$0$$0$$1$$1$$0$$0$$0$