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(B) First,identify the orbitals based on the given quantum numbers:$(i)$ $n = 4, l = 1$ corresponds to $4p$ orbital. $(n+l) = 4 + 1 = 5$.$(ii)$ $n = 4

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$(iv) < (ii) < (iii) < (i)$

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(B) First,identify the orbitals based on the given quantum numbers:$(i)$ $n = 4, l = 1$ corresponds to $4p$ orbital. $(n+l) = 4 + 1 = 5$.$(ii)$ $n = 4, l = 0$ corresponds to $4s$ orbital. $(n+l) = 4 + 0 = 4$.$(iii)$ $n = 3, l = 2$ corresponds to $3d$ orbital. $(n+l) = 3 + 2 = 5$.$(iv)$ $n = 3, l = 1$ corresponds to $3p$ orbital. $(n+l) = 3 + 1 = 4$.According to the $(n+l)$ rule,energy increases as the $(n+l)$ value increases.For $(iv)$ and $(ii)$,both have $(n+l) = 4$. Since $(iv)$ has a lower $n$ value $(n=3)$ than $(ii)$ $(n=4)$,$(iv)$ has lower energy.For $(iii)$ and $(i)$,both have $(n+l) = 5$. Since $(iii)$ has a lower $n$ value $(n=3)$ than $(i)$ $(n=4)$,$(iii)$ has lower energy.Thus,the increasing order of energy is: $(iv) < (ii) < (iii) < (i)$.

The following sets of quantum numbers represent four electrons in an atom:
$(i)$ $n = 4, l = 1$ $(ii)$ $n = 4, l = 0$
$(iii)$ $n = 3, l = 2$ $(iv)$ $n = 3, l = 1$
The sequence representing the increasing order of energy is:

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The following sets of quantum numbers represent four electrons in an atom:$(i)$ $n = 4, l = 1$ $(ii)$ $n = 4, l = 0$$(iii)$ $n = 3, l = 2$ $(iv)$ $n = 3, l = 1$The sequence representing the increasing order of energy is: