The focal distance of a point P on the parabo | vedclass

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(B) The given equation of the parabola is $y^{2}=12x$. Comparing this with $y^{2}=4ax$,we get $4a=12$,which implies $a=3$. For the point $P(x, y)$,the

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$6$

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(B) The given equation of the parabola is $y^{2}=12x$. Comparing this with $y^{2}=4ax$,we get $4a=12$,which implies $a=3$. For the point $P(x, y)$,the ordinate is given as $y=6$. Since the point $P$ lies on the parabola,we substitute $y=6$ into the equation: $(6)^{2}=12x$ $\Rightarrow 36=12x$ $\Rightarrow x=3$. The focal distance of a point $P(x, y)$ on the parabola $y^{2}=4ax$ is given by the formula $x+a$. Substituting the values $x=3$ and $a=3$,we get: Focal distance $= 3+3=6$.

The focal distance of a point $P$ on the parabola $y^{2}=12x$ if the ordinate of $P$ is $6$,is

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