The first ionization energy of magnesium is smaller as compared to that of elements $X$ and $Y$,but higher than that of $Z$. The elements $X$,$Y$ and $Z$,respectively,are :

  • A
    chlorine,lithium and sodium
  • B
    argon,lithium and sodium
  • C
    argon,chlorine and sodium
  • D
    neon,sodium and chlorine

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The $1^{\text{st}}$,$2^{\text{nd}}$,and $3^{\text{rd}}$ ionization enthalpies $I_1, I_2$,and $I_3$ of four atoms with atomic numbers $n, n+1, n+2$,and $n+3$,where $n < 10$,are tabulated below. What is the value of $n$?
Atomic number $I_1$ $(kJ/mol)$ $I_2$ $(kJ/mol)$ $I_3$ $(kJ/mol)$
$n$ $I_1$ $I_2$ $I_3$
$n+1$ $1681$ $3374$ $6050$
$n+2$ $2081$ $3952$ $6122$
$n+3$ $496$ $4562$ $6910$
$n+4$ $738$ $1451$ $7733$

The correct sequence of elements in decreasing order of first ionisation energy is

What is the increasing order of the first ionization enthalpy of $B, P, S$ and $F$ (lowest first)?

Which of the following presents the correct order of second ionization enthalpies of $C$,$N$,$O$ and $F$?

How would you explain the fact that the first ionization enthalpy of sodium is lower than that of magnesium but its second ionization enthalpy is higher than that of magnesium?

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