The final product (C) in the given reaction s | vedclass

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(B) Step $1$: $C_6H_5COOH + SOCl_2 \rightarrow C_6H_5COCl (A) + SO_2 + HCl$. This is the conversion of benzoic acid to benzoyl chloride.Step $2$: $C_6

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Diphenyl methane

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(B) Step $1$: $C_6H_5COOH + SOCl_2 ightarrow C_6H_5COCl (A) + SO_2 + HCl$. This is the conversion of benzoic acid to benzoyl chloride.Step $2$: $C_6H_5COCl + C_6H_6 \xrightarrow{	ext{anhy. } AlCl_3} C_6H_5COC_6H_5 (B) + HCl$. This is a Friedel-Crafts acylation reaction producing benzophenone.Step $3$: $C_6H_5COC_6H_5 \xrightarrow[	ext{(ii) } KOH / (CH_2OH)_2]{	ext{(i) } NH_2-NH_2} C_6H_5CH_2C_6H_5 (C)$. This is the Wolff-Kishner reduction of benzophenone to diphenylmethane.

The final product $(C)$ in the given reaction sequence is
$C_6H_5COOH$ $\xrightarrow{SOCl_2} (A)$ $\xrightarrow[\text{anhy. } AlCl_3]{C_6H_6} (B)$ $\xrightarrow[\text{(ii) } KOH / (CH_2OH)_2]{\text{(i) } NH_2-NH_2} (C)$

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The final product $(C)$ in the given reaction sequence is$C_6H_5COOH$ $\xrightarrow{SOCl_2} (A)$ $\xrightarrow[\text{anhy. } AlCl_3]{C_6H_6} (B)$ $\xrightarrow[\text{(ii) } KOH / (CH_2OH)_2]{\text{(i) } NH_2-NH_2} (C)$