The final product R of the reaction is: | vedclass

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(B) $1$. Benzoic acid $(C_6H_5COOH)$ reacts with $NH_3$ followed by heating to form benzamide $(C_6H_5CONH_2)$,which is product $P$.$2$. Benzamide und

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Benzanilide

Vedclass · Answer

(B) $1$. Benzoic acid $(C_6H_5COOH)$ reacts with $NH_3$ followed by heating to form benzamide $(C_6H_5CONH_2)$,which is product $P$.$2$. Benzamide undergoes the Hofmann bromamide degradation reaction with $NaOBr$ to form aniline $(C_6H_5NH_2)$,which is product $Q$.$3$. Aniline reacts with benzoyl chloride $(C_6H_5COCl)$ in the presence of a base to form $N$-phenylbenzamide,commonly known as benzanilide $(C_6H_5NHCOC_6H_5)$,which is the final product $R$.

The final product $R$ of the reaction is:

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