The final product C,obtained in the following | vedclass

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(A) The reaction sequence is as follows:$1$. $p$-Toluidine reacts with acetic anhydride $(Ac_2O)$ to form $N$-($4$-methylphenyl)acetamide (acetanilide

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$2-$Bromo$-4-$methylaniline

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(A) The reaction sequence is as follows:$1$. $p$-Toluidine reacts with acetic anhydride $(Ac_2O)$ to form $N$-($4$-methylphenyl)acetamide (acetanilide derivative),which is compound $A$.$2$. Compound $A$ undergoes electrophilic aromatic substitution with $Br_2$ in $CH_3COOH$. The $-NHCOCH_3$ group is strongly activating and ortho/para directing. Since the para position is occupied by the $-CH_3$ group,bromine enters the ortho position relative to the $-NHCOCH_3$ group,forming $2$-bromo-$4$-methylacetanilide,which is compound $B$.$3$. Finally,acid-catalyzed hydrolysis of compound $B$ removes the acetyl group to regenerate the amine,yielding $2$-bromo-$4$-methylaniline as the final product $C$.

The final product $C$,obtained in the following reaction sequence,would be:
$p$-Toluidine $\xrightarrow{Ac_2O} A$ $\xrightarrow{Br_2/CH_3COOH} B$ $\xrightarrow{H_2O/H^+} C$

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The final product $C$,obtained in the following reaction sequence,would be:$p$-Toluidine $\xrightarrow{Ac_2O} A$ $\xrightarrow{Br_2/CH_3COOH} B$ $\xrightarrow{H_2O/H^+} C$