The figure shows a velocity-time graph of a particle moving along a straight line The maximum displacement of the particle is ........ $m$
The figure shows a velocity-time graph of a particle moving along a straight line The maximum displacement of the particle is ........ $m$
- A
$33.3$
- B
$23.3$
- C
$18.3$
- D
$0$
Similar Questions
A vector has magnitude and direction. Does it have a location in space ? Can it vary with time ? Will two equal vectors $a$ and $b$ at different locations in space necessarily have identical physical effects ? Give examples in support of your answer.
A vector has magnitude and direction. Does it have a location in space ? Can it vary with time ? Will two equal vectors $a$ and $b$ at different locations in space necessarily have identical physical effects ? Give examples in support of your answer.
The position of a particle is given by
$r=3.0 t \hat{i}+2.0 t^{2} \hat{j}+5.0 \hat{k}$
where $t$ is in seconds and the coefficients have the proper units for $r$ to be in metres.
$(a)$ Find $v (t)$ and $a (t)$ of the particle.
$(b)$ Find the magnitude and direction of $v (t)$ at $t=1.0 s$
The position of a particle is given by
$r=3.0 t \hat{i}+2.0 t^{2} \hat{j}+5.0 \hat{k}$
where $t$ is in seconds and the coefficients have the proper units for $r$ to be in metres.
$(a)$ Find $v (t)$ and $a (t)$ of the particle.
$(b)$ Find the magnitude and direction of $v (t)$ at $t=1.0 s$
A person goes $10\, km$ north and $20\, km$ east. What will be displacement from initial point........$km$
If two forces of equal magnitudes act simultaneously on a body in the east and the north directions then
- [AIIMS 2009]
The position of a projectile launched from the origin at $t=0$ is given by $\vec{r}=(40 \hat{i}+50 \hat{j}) m$ at $t=$ $2 s$. If the projectile was launched at an angle $\theta$ from the horizontal, then $\theta$ is (take $g =10\,ms ^{-2}$ )
The position of a projectile launched from the origin at $t=0$ is given by $\vec{r}=(40 \hat{i}+50 \hat{j}) m$ at $t=$ $2 s$. If the projectile was launched at an angle $\theta$ from the horizontal, then $\theta$ is (take $g =10\,ms ^{-2}$ )