The figure shows a velocity-time graph of a particle moving along a straight line. If the particle starts from the position $x_0 = -15 \, m$,then its position at $t = 2 \, s$ will be ........ $m$.

What does $\dot x$ represent?

The displacement-time graph for two particles $A$ and $B$ are straight lines inclined at angles of $30^\circ$ and $60^\circ$ with the time axis. The ratio of velocities $V_A:V_B$ is

The velocity $v$ of a particle is given by the equation $v = 6t^2 - 6t^3$,where $v$ is in $m/s$ and $t$ is time in $s$. Then:

The velocity-time graph for a particle moving in a straight line is shown in the figure. The average velocity between $t=4 \,s$ and $t=6 \,s$ is . . . . . . (in $\,ms^{-1}$)

$A$ bullet is shot vertically downwards with an initial velocity of $100\,m/s$ from a certain height. Within $10\,s$,the bullet reaches the ground and instantaneously comes to rest due to a perfectly inelastic collision. The velocity-time curve for the total time $t = 20\,s$ will be: (Take $g = 10\,m/s^2$)