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Question

(a) Consider a concentric spherical shell of radius $r$ and thickness $dr$ as shown in fig.
The radial rate of flow of heat through this shell in ste

Vedclass · Accepted Answer

$\frac{{{r_1}\,{r_2}}}{{({r_1} - {r_2})}}$

Vedclass · Answer

(a) Consider a concentric spherical shell of radius $r$ and thickness $dr$ as shown in fig.
The radial rate of flow of heat through this shell in steady state will be $H = \frac{{dQ}}{{dt}} = - KA\frac{{dT}}{{dr}} = - K\,(4\pi {r^2})\frac{{dT}}{{dr}}$

==> $\int_{\,{r_1}}^{\,{r_2}} {\frac{{dr}}{{{r^2}}} = - \frac{{4\pi K}}{H}\int_{\,{T_1}}^{{T_1}} {dT} } $

Which on integration and simplification gives

$H = \frac{{dQ}}{{dt}} = \frac{{4\pi K{r_1}{r_2}({T_1} - {T_2})}}{{{r_2} - {r_1}}}$

==> $\frac{{dQ}}{{dt}} \propto \frac{{{r_1}{r_2}}}{{({r_2} - {r_1})}}$

The figure shows a system of two concentric spheres of radii $r_1$ and $r_2$ and kept at temperatures $T_1$ and $T_2$, respectively. The radial rate of flow of heat in a substance between the two concentric spheres is proportional to

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