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(C) wavefront is defined as the locus of all points having the same phase of oscillation. Since $cd$ is a wavefront in medium-$1$,all points on the li

Vedclass · Accepted Answer

$(\phi_d - \phi_f) = (\phi_c - \phi_e)$

Vedclass · Answer

(C) wavefront is defined as the locus of all points having the same phase of oscillation. Since $cd$ is a wavefront in medium-$1$,all points on the line $cd$ have the same phase. Therefore,$\phi_c = \phi_d$. Similarly,$ef$ is a wavefront in medium-$2$,so all points on the line $ef$ have the same phase. Therefore,$\phi_e = \phi_f$. Now,consider the expression $(\phi_d - \phi_f) = (\phi_c - \phi_e)$. Since $\phi_c = \phi_d$ and $\phi_e = \phi_f$,we can substitute these into the expression: $(\phi_d - \phi_f) = (\phi_c - \phi_e)$ $\phi_d - \phi_f = \phi_c - \phi_e$ This is a consistent identity based on the properties of wavefronts.

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