(C) The path difference $\Delta x$ between the two waves reaching point $X$ is given by:$\Delta x = |QX - PX| = |(n + 2)\lambda - n\lambda| = 2\lambda

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(C) The path difference $\Delta x$ between the two waves reaching point $X$ is given by:$\Delta x = |QX - PX| = |(n + 2)\lambda - n\lambda| = 2\lambda$.For constructive interference (bright fringe),the condition is $\Delta x = m\lambda$,where $m = 0, 1, 2, ...$.Here,$\Delta x = 2\lambda$,which corresponds to $m = 2$.Since the central fringe $(m = 0)$ is at the center,$m = 1$ corresponds to the first bright fringe,and $m = 2$ corresponds to the second bright fringe.Therefore,the second bright fringe is formed at $X$.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

Medium

The figure shows a double slit experiment where $P$ and $Q$ are the slits. The path lengths $PX$ and $QX$ are $n\lambda$ and $(n + 2)\lambda$ respectively,where $n$ is a whole number and $\lambda$ is the wavelength. Taking the central fringe as zero,what is formed at $X$?

A
First bright
B
First dark
C
Second bright
D
Second dark

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Class 12 Questions

Class 12

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Wave Optics

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Young's Double Slit Experiment (YDSE)

Two slits separated by a distance of $1\, mm$ are illuminated with red light of wavelength $6.5 \times 10^{-7}\, m$. The interference fringes are observed on a screen placed $1\, m$ from the slits. Find the distance between the third dark fringe and the fifth bright fringe on the same side of the central maxima.

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Two slits are separated by a distance of $0.5\, mm$ and illuminated with light of $\lambda = 6000\ \mathring A$. If the screen is placed $2.5\, m$ from the slits,the distance of the third bright fringe from the centre will be........$mm$.

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$A$ laser light of wavelength $630 \, nm$ is incident on a pair of slits,and the fringe width of the interference pattern produced is $8.1 \, mm$. In another interference pattern produced by a different light,the fringe width is $7.2 \, mm$. Find the wavelength of this second light in $nm$.

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In Young's double-slit experiment,if the amplitudes of the interfering waves are not equal,then . . . . .

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In Young's double slit experiment,the light emitted from the source has $\lambda = 6.5 \times 10^{-7} \, m$ and the distance between the two slits is $1 \, mm$. The distance between the screen and the slits is $1 \, m$. The distance between the third dark fringe and the fifth bright fringe will be ......... $mm$.

Difficult

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The figure shows a double slit experiment where $P$ and $Q$ are the slits. The path lengths $PX$ and $QX$ are $n\lambda$ and $(n + 2)\lambda$ respectively,where $n$ is a whole number and $\lambda$ is the wavelength. Taking the central fringe as zero,what is formed at $X$?

Similar Questions

Two slits are separated by a distance of $0.5\, mm$ and illuminated with light of $\lambda = 6000\ \mathring A$. If the screen is placed $2.5\, m$ from the slits,the distance of the third bright fringe from the centre will be........$mm$.

$A$ laser light of wavelength $630 \, nm$ is incident on a pair of slits,and the fringe width of the interference pattern produced is $8.1 \, mm$. In another interference pattern produced by a different light,the fringe width is $7.2 \, mm$. Find the wavelength of this second light in $nm$.

In Young's double-slit experiment,if the amplitudes of the interfering waves are not equal,then . . . . .

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