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(C, D) For a wave traveling in the negative $x$-direction, the velocity of a particle at any point $x$ is given by $v_p = -v \cdot (	ext{slope})$, wh

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$c$

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(C, D) For a wave traveling in the negative $x$-direction, the velocity of a particle at any point $x$ is given by $v_p = -v \cdot (	ext{slope})$, where $v$ is the wave speed and the slope is $\frac{\partial y}{\partial x}$.Since the wave is moving in the negative $x$-direction, $v$ is negative. Thus, $v_p = |v| \cdot (	ext{slope})$.Therefore, a particle moves downwards $(v_p Looking at the graph:- At point $a$, the slope is positive, so it moves upwards.- At point $b$, the slope is zero (it is a crest).- At point $c$, the slope is negative, so it moves downwards.- At point $d$, the slope is negative, so it moves downwards.- At point $e$, the slope is positive, so it moves upwards.- At point $f$, the slope is zero (it is a trough).- At point $g$, the slope is positive, so it moves upwards.- At point $h$, the slope is positive, so it moves upwards.Thus, points $c$ and $d$ are moving downwards.

The figure represents the instantaneous snapshot of a transverse harmonic wave traveling along the negative $x$-axis. Choose the correct alternative(s) related to the movement of the points shown in the figure. The point(s) moving downwards is/are:

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