The figure below shows the north and south po | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The torque $	au$ on a current-carrying coil in a magnetic field is given by $	au = \vec{M} 	imes \vec{B}$,where $\vec{M}$ is the magnetic dipol

Vedclass · Accepted Answer

$	au = niAB \cos 	heta$

Vedclass · Answer

(A) The torque $	au$ on a current-carrying coil in a magnetic field is given by $	au = \vec{M} 	imes \vec{B}$,where $\vec{M}$ is the magnetic dipole moment and $\vec{B}$ is the magnetic field.The magnitude of the torque is $	au = MB \sin \alpha$,where $\alpha$ is the angle between the magnetic moment vector $\vec{M}$ (which is perpendicular to the plane of the coil) and the magnetic field vector $\vec{B}$.Given that the plane of the coil makes an angle $	heta$ with the magnetic field $B$,the angle $\alpha$ between the normal to the coil (the direction of $\vec{M}$) and the magnetic field $\vec{B}$ is $\alpha = 90^\circ - 	heta$.Substituting this into the torque formula: $	au = MB \sin(90^\circ - 	heta) = MB \cos 	heta$.Since the magnetic moment $M = niA$,we have $	au = niAB \cos 	heta$.

Similar Questions

$A$ wire of length $L$ is bent in the form of a circular coil and current $i$ is passed through it. If this coil is placed in a magnetic field,then the torque acting on the coil will be maximum when the number of turns is

Current $i$ is carried in a wire of length $L$. If the wire is turned into a circular coil,the maximum magnitude of torque in a given magnetic field $B$ will be

$A$ wire of length $L$ carries a current $i$. If the wire is turned into a circular coil and kept in a uniform magnetic field $B$,the maximum magnitude of torque in the given magnetic field will be

$A$ uniform magnetic field of $0.3 \text{ T}$ is established along the $+z$-direction. $A$ rectangular loop of sides $10 \text{ cm}$ and $5 \text{ cm}$ carries a current of $12 \text{ A}$ and is placed in the $xy$-plane as shown in the figure. The torque acting on the loop is $....... \text{ Nm}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module