The far point of a myopic person is 80, cm in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a myopic person,the far point is at a finite distance $v = -80\, cm$.To see objects at infinity $(u = \infty)$ clearly,the lens must form a vi

Vedclass · Accepted Answer

$-1.25\, D$

Vedclass · Answer

(A) For a myopic person,the far point is at a finite distance $v = -80\, cm$.To see objects at infinity $(u = \infty)$ clearly,the lens must form a virtual image at the person's far point.Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.Substituting the values: $\frac{1}{f} = \frac{1}{-80} - \frac{1}{\infty} = \frac{1}{-80} - 0 = -\frac{1}{80}\, cm^{-1}$.Thus,the focal length $f = -80\, cm = -0.8\, m$.The power of the lens is given by $P = \frac{1}{f(m)}$.$P = \frac{1}{-0.8} = -1.25\, D$.

The far point of a myopic person is $80\, cm$ in front of the eye. What is the power of the lens required to enable him to see very distant objects clearly?

Similar Questions

$A$ far-sighted man who has lost his spectacles reads a book by looking through a small hole $(3-4 \,mm)$ in a sheet of paper. The reason is:

When objects at different distances are seen by the eye,which of the following remains constant?

The ability of the eye to see objects at all distances is called

Astigmatism (for a human eye) can be removed by using

The human eye has a lens which has a

Vedclass Test Series

Exam Paper Generator

Online Exam Module