The equivalent weight of an element is 4. Its | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The formula for the molecular weight of a chloride is $M = 2 	imes V.D = 2 	imes 59.25 = 118.5$.Let the valency of the element be $n$ and its eq

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) The formula for the molecular weight of a chloride is $M = 2 	imes V.D = 2 	imes 59.25 = 118.5$.Let the valency of the element be $n$ and its equivalent weight be $E = 4$.The molecular weight of the chloride $(MCl_n)$ is given by $M = E 	imes n + 35.5 	imes n$.Substituting the values: $118.5 = 4n + 35.5n$.$118.5 = 39.5n$.$n = \frac{118.5}{39.5} = 3$.Therefore,the valency of the element is $3$.

The equivalent weight of an element is $4$. Its chloride has a $V.D$ of $59.25$. Then the valency of the element is:

Similar Questions

What is the mass of one molecule of the compound $C_{60}H_{122}$ in grams?

$A$ metal oxide is reduced by heating it in a stream of hydrogen. It is found that after complete reduction,$3.15 \, g$ of the oxide yielded $1.05 \, g$ of the metal. We may deduce that:

The number of electrons in one molecule of $CO_2$ is:

Naturally occurring boron has $20\%\, _5B^{10}$ and $80\%\, _5B^{11}$. The atomic weight of boron is :-

Explain the concept of Average Atomic Mass.

Vedclass Test Series

Exam Paper Generator

Online Exam Module